Pinter Declaration in C

Not writing C for a period of time. I found a interesting gadget when declaring two pointer today.

Usually we will declare a pointer in C like this:

TYPE* var;

and declare a list of varibles with same type like this:

TYPE var1, var2, ..., varn;

So I try to declare two pointer with same type like this:

TYPE* var1, var2;

Finally I found it wrong, typeof(var1) is TYPE* , but typeof(var2) is TYPE.

It is not working even if i use the following method

(TYPE*) var1, var2;

As we can see, TYPE* does not denote a pointer TYPE, the declaration of pointer is divided into two part: First is declare a pointer*val, second identify the type of the object that this pointer point toTYPE (*val).

This problem is due to the writing habbit, we usually write * beside with TYPE which will cause the illusion of TYPE* is a pointer type. But we should write TYPE *val as a pointer(first declare a pointer) to a TYPE object(second declare object type).

Let’s write with the right format to declare two same type pointers:

TYPE *val1,*val2;